Equation of Ellipse & Hyperbola: Complex Number

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Equation of Ellipse:

Ellipse is locus of a point whose sum of distance from two fixed points is constant.
                                                  OR
Ellipse is a curve on a plane surrounding two focal points such that a straight line drawn from one focal point to any point of the curve and then back to other focal point has the same length for every point of the curve.

|z - {z_1}| + |z - {z_2}| = 2a

|z - z1| + |z - z2| = 2a

where, 2a > |z1 - z2|

(if 2a = |z1 - z2| , equation represent a line segment
and if 2a < |z1 - z2|, there is no value of z i.e. sum of distance from two fixed points cannot be lesser than distance between those two fixed points)

Focii -> z1 and z2

2a -> Major axis


Ques: |z - 1| + |z + 1| = 4, find the locus of z ?

Solution: Locus of z is ellipse,

Focii -> -1 and 1 or (-1,0) and (1,0)

Major axis, 2a = 4 => a = 2

therefore, ae = 1,

=> e = 1/2

since,  b = \sqrt {{a^2}(1 - {e^2})}  = \sqrt {4(1 - 1/4)}  = \sqrt 3

Since equation of ellipse, \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

therefore, \frac{{{x^2}}}{4} + \frac{{{y^2}}}{3} = 1

or, \frac{{{x^2}}}{4} + \frac{{{y^2}}}{3} = 1


Ques: |z - i| + |z + i| = 3

Sol: Major axis, 2b = 3

=> b = 3/2

Focii, i and -i or (0,1) and (0,-1)

be = 1

=> e = 2/3

Since, {a^2} = {b^2}(1 - {e^2})

a = 5/4

Therefore equation,

\frac{{4{x^2}}}{5} + \frac{{4{y^2}}}{9} = 1


Equation of Hyperbola:-

|z - z1| - |z - z2| = 2a

where, 2a < |z1 - z2|

Focii, z1 & z2

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