Geometrical Meaning of Argument and Modulus - I: Complex Number






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Students are requested to understand this carefully 


1. Arg(z) = pi/3

z = 0 is excluded

since z = 0 is the only complex number whose argument is not defined




2. Arg(z) > pi/3

Since principal argument belongs to (-pi, pi], therefore Argument cannot be greater than pi.

therefore Arg(z) > pi/3 =>) \pi /3 < Arg(z) \le \pi

z = 0 is excluded


3. |Arg(z)| < pi/4

=> -pi/4 < Arg(z) < pi/4

z = 0 is excluded
4. |Arg(z)| \ge \pi

=> Arg(z) = pi

since, principal argument belongs to ( - \pi ,\pi ], therefore Argument cannot be greater than pi.

z = 0 is excluded
5.  - \pi /3 \le Arg(z) <  - \pi /6

-pi/3 is included

z = 0 is excluded



6. Complex number {(z)^2} \ne |z{|^2} , equal only when z is purely real number or '0'




IMP
7. Arg(|z|) = 0

Since |z| is a Positive Real number, therefore it lies on right side of x - axis i.e. on positive Real axis and x-axis has '0' argument because it makes 0 radian angle from x-axis

For z = 0 , argument does not exist

Therefore equation is satisfied for all values of z except z = 0



8. Arg\left| {\frac{{z - i}}{{z + i}}} \right| = 0

Any Positive Real number has argument 0 and any negative real number has argument pi

Modulus of Any complex number except '0' is a Positive Real number therefore Argument of mod of any complex number is '0'


Since, Arg\frac{{{z_1}}}{{{z_2}}} = Arg({z_1}) - Arg({z_2})

therefore, Arg|z - i| - Arg|z + i| = 0

Arg|z - i| = Arg|z + i|

This is always true because argument of modulus of any complex number is 0.

Therefore LHS and RHS both are zero for all z except i and -i because at '0' argument does not exist

Therefore equation is true for all value of z except i and -i




9. Im(z) > 1

If z = x + iy

then, y > 1
10. Im(z - 2) > 1

same region as of point 9 

z = x + iy

=> z -2 = (x - 2) + iy

=> y > 1




11. Im(z - i) > 1

=> y - 1 > 1

or, y > 2

since z - i = x + i (y - 2)




12. -1 < Im(z + i) < 1

=> -1 < y + 1 < 1

=> -2 < y < 0
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Comments

  1. Some missings:
    1) In section 5 write -pi/6.
    2) In section 8 complete the sentence as 'Modulous of any complex no. is a positive real number........... is 0.
    Rest is good.

    ReplyDelete
  2. it was hard to find a simple explanation like this one, thank you very much from Argentina

    ReplyDelete

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